4x^2+4x+1=16

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Solution for 4x^2+4x+1=16 equation:


Simplifying
4x2 + 4x + 1 = 16

Reorder the terms:
1 + 4x + 4x2 = 16

Solving
1 + 4x + 4x2 = 16

Solving for variable 'x'.

Reorder the terms:
1 + -16 + 4x + 4x2 = 16 + -16

Combine like terms: 1 + -16 = -15
-15 + 4x + 4x2 = 16 + -16

Combine like terms: 16 + -16 = 0
-15 + 4x + 4x2 = 0

Factor a trinomial.
(-5 + -2x)(3 + -2x) = 0

Subproblem 1

Set the factor '(-5 + -2x)' equal to zero and attempt to solve: Simplifying -5 + -2x = 0 Solving -5 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2x = 0 + 5 -2x = 0 + 5 Combine like terms: 0 + 5 = 5 -2x = 5 Divide each side by '-2'. x = -2.5 Simplifying x = -2.5

Subproblem 2

Set the factor '(3 + -2x)' equal to zero and attempt to solve: Simplifying 3 + -2x = 0 Solving 3 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2x = 0 + -3 -2x = 0 + -3 Combine like terms: 0 + -3 = -3 -2x = -3 Divide each side by '-2'. x = 1.5 Simplifying x = 1.5

Solution

x = {-2.5, 1.5}

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